3.7.21 \(\int \frac {\log ^3(f x^p) (a+b \log (c (d+e x^m)^n))}{x} \, dx\) [621]

Optimal. Leaf size=161 \[ \frac {\log ^4\left (f x^p\right ) \left (a+b \log \left (c \left (d+e x^m\right )^n\right )\right )}{4 p}-\frac {b n \log ^4\left (f x^p\right ) \log \left (1+\frac {e x^m}{d}\right )}{4 p}-\frac {b n \log ^3\left (f x^p\right ) \text {Li}_2\left (-\frac {e x^m}{d}\right )}{m}+\frac {3 b n p \log ^2\left (f x^p\right ) \text {Li}_3\left (-\frac {e x^m}{d}\right )}{m^2}-\frac {6 b n p^2 \log \left (f x^p\right ) \text {Li}_4\left (-\frac {e x^m}{d}\right )}{m^3}+\frac {6 b n p^3 \text {Li}_5\left (-\frac {e x^m}{d}\right )}{m^4} \]

[Out]

1/4*ln(f*x^p)^4*(a+b*ln(c*(d+e*x^m)^n))/p-1/4*b*n*ln(f*x^p)^4*ln(1+e*x^m/d)/p-b*n*ln(f*x^p)^3*polylog(2,-e*x^m
/d)/m+3*b*n*p*ln(f*x^p)^2*polylog(3,-e*x^m/d)/m^2-6*b*n*p^2*ln(f*x^p)*polylog(4,-e*x^m/d)/m^3+6*b*n*p^3*polylo
g(5,-e*x^m/d)/m^4

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Rubi [A]
time = 0.15, antiderivative size = 161, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.179, Rules used = {2531, 2375, 2421, 2430, 6724} \begin {gather*} -\frac {6 b n p^2 \log \left (f x^p\right ) \text {PolyLog}\left (4,-\frac {e x^m}{d}\right )}{m^3}+\frac {3 b n p \log ^2\left (f x^p\right ) \text {PolyLog}\left (3,-\frac {e x^m}{d}\right )}{m^2}-\frac {b n \log ^3\left (f x^p\right ) \text {PolyLog}\left (2,-\frac {e x^m}{d}\right )}{m}+\frac {6 b n p^3 \text {PolyLog}\left (5,-\frac {e x^m}{d}\right )}{m^4}+\frac {\log ^4\left (f x^p\right ) \left (a+b \log \left (c \left (d+e x^m\right )^n\right )\right )}{4 p}-\frac {b n \log ^4\left (f x^p\right ) \log \left (\frac {e x^m}{d}+1\right )}{4 p} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(Log[f*x^p]^3*(a + b*Log[c*(d + e*x^m)^n]))/x,x]

[Out]

(Log[f*x^p]^4*(a + b*Log[c*(d + e*x^m)^n]))/(4*p) - (b*n*Log[f*x^p]^4*Log[1 + (e*x^m)/d])/(4*p) - (b*n*Log[f*x
^p]^3*PolyLog[2, -((e*x^m)/d)])/m + (3*b*n*p*Log[f*x^p]^2*PolyLog[3, -((e*x^m)/d)])/m^2 - (6*b*n*p^2*Log[f*x^p
]*PolyLog[4, -((e*x^m)/d)])/m^3 + (6*b*n*p^3*PolyLog[5, -((e*x^m)/d)])/m^4

Rule 2375

Int[(((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((f_.)*(x_))^(m_.))/((d_) + (e_.)*(x_)^(r_)), x_Symbol] :> Si
mp[f^m*Log[1 + e*(x^r/d)]*((a + b*Log[c*x^n])^p/(e*r)), x] - Dist[b*f^m*n*(p/(e*r)), Int[Log[1 + e*(x^r/d)]*((
a + b*Log[c*x^n])^(p - 1)/x), x], x] /; FreeQ[{a, b, c, d, e, f, m, n, r}, x] && EqQ[m, r - 1] && IGtQ[p, 0] &
& (IntegerQ[m] || GtQ[f, 0]) && NeQ[r, n]

Rule 2421

Int[(Log[(d_.)*((e_) + (f_.)*(x_)^(m_.))]*((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.))/(x_), x_Symbol] :> Simp
[(-PolyLog[2, (-d)*f*x^m])*((a + b*Log[c*x^n])^p/m), x] + Dist[b*n*(p/m), Int[PolyLog[2, (-d)*f*x^m]*((a + b*L
og[c*x^n])^(p - 1)/x), x], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x] && IGtQ[p, 0] && EqQ[d*e, 1]

Rule 2430

Int[(((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*PolyLog[k_, (e_.)*(x_)^(q_.)])/(x_), x_Symbol] :> Simp[PolyLo
g[k + 1, e*x^q]*((a + b*Log[c*x^n])^p/q), x] - Dist[b*n*(p/q), Int[PolyLog[k + 1, e*x^q]*((a + b*Log[c*x^n])^(
p - 1)/x), x], x] /; FreeQ[{a, b, c, e, k, n, q}, x] && GtQ[p, 0]

Rule 2531

Int[(Log[(f_.)*(x_)^(q_.)]^(m_.)*((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.)))/(x_), x_Symbol] :>
Simp[Log[f*x^q]^(m + 1)*((a + b*Log[c*(d + e*x^n)^p])/(q*(m + 1))), x] - Dist[b*e*n*(p/(q*(m + 1))), Int[x^(n
- 1)*(Log[f*x^q]^(m + 1)/(d + e*x^n)), x], x] /; FreeQ[{a, b, c, d, e, f, m, n, p, q}, x] && NeQ[m, -1]

Rule 6724

Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[PolyLog[n + 1, c*(a
+ b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d, e, n, p}, x] && EqQ[b*d, a*e]

Rubi steps

\begin {align*} \int \frac {\log ^3\left (f x^p\right ) \left (a+b \log \left (c \left (d+e x^m\right )^n\right )\right )}{x} \, dx &=\frac {\log ^4\left (f x^p\right ) \left (a+b \log \left (c \left (d+e x^m\right )^n\right )\right )}{4 p}-\frac {(b e m n) \int \frac {x^{-1+m} \log ^4\left (f x^p\right )}{d+e x^m} \, dx}{4 p}\\ &=\frac {\log ^4\left (f x^p\right ) \left (a+b \log \left (c \left (d+e x^m\right )^n\right )\right )}{4 p}-\frac {b n \log ^4\left (f x^p\right ) \log \left (1+\frac {e x^m}{d}\right )}{4 p}+(b n) \int \frac {\log ^3\left (f x^p\right ) \log \left (1+\frac {e x^m}{d}\right )}{x} \, dx\\ &=\frac {\log ^4\left (f x^p\right ) \left (a+b \log \left (c \left (d+e x^m\right )^n\right )\right )}{4 p}-\frac {b n \log ^4\left (f x^p\right ) \log \left (1+\frac {e x^m}{d}\right )}{4 p}-\frac {b n \log ^3\left (f x^p\right ) \text {Li}_2\left (-\frac {e x^m}{d}\right )}{m}+\frac {(3 b n p) \int \frac {\log ^2\left (f x^p\right ) \text {Li}_2\left (-\frac {e x^m}{d}\right )}{x} \, dx}{m}\\ &=\frac {\log ^4\left (f x^p\right ) \left (a+b \log \left (c \left (d+e x^m\right )^n\right )\right )}{4 p}-\frac {b n \log ^4\left (f x^p\right ) \log \left (1+\frac {e x^m}{d}\right )}{4 p}-\frac {b n \log ^3\left (f x^p\right ) \text {Li}_2\left (-\frac {e x^m}{d}\right )}{m}+\frac {3 b n p \log ^2\left (f x^p\right ) \text {Li}_3\left (-\frac {e x^m}{d}\right )}{m^2}-\frac {\left (6 b n p^2\right ) \int \frac {\log \left (f x^p\right ) \text {Li}_3\left (-\frac {e x^m}{d}\right )}{x} \, dx}{m^2}\\ &=\frac {\log ^4\left (f x^p\right ) \left (a+b \log \left (c \left (d+e x^m\right )^n\right )\right )}{4 p}-\frac {b n \log ^4\left (f x^p\right ) \log \left (1+\frac {e x^m}{d}\right )}{4 p}-\frac {b n \log ^3\left (f x^p\right ) \text {Li}_2\left (-\frac {e x^m}{d}\right )}{m}+\frac {3 b n p \log ^2\left (f x^p\right ) \text {Li}_3\left (-\frac {e x^m}{d}\right )}{m^2}-\frac {6 b n p^2 \log \left (f x^p\right ) \text {Li}_4\left (-\frac {e x^m}{d}\right )}{m^3}+\frac {\left (6 b n p^3\right ) \int \frac {\text {Li}_4\left (-\frac {e x^m}{d}\right )}{x} \, dx}{m^3}\\ &=\frac {\log ^4\left (f x^p\right ) \left (a+b \log \left (c \left (d+e x^m\right )^n\right )\right )}{4 p}-\frac {b n \log ^4\left (f x^p\right ) \log \left (1+\frac {e x^m}{d}\right )}{4 p}-\frac {b n \log ^3\left (f x^p\right ) \text {Li}_2\left (-\frac {e x^m}{d}\right )}{m}+\frac {3 b n p \log ^2\left (f x^p\right ) \text {Li}_3\left (-\frac {e x^m}{d}\right )}{m^2}-\frac {6 b n p^2 \log \left (f x^p\right ) \text {Li}_4\left (-\frac {e x^m}{d}\right )}{m^3}+\frac {6 b n p^3 \text {Li}_5\left (-\frac {e x^m}{d}\right )}{m^4}\\ \end {align*}

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Mathematica [B] Leaf count is larger than twice the leaf count of optimal. \(659\) vs. \(2(161)=322\).
time = 0.18, size = 659, normalized size = 4.09 \begin {gather*} -\frac {3}{10} b m n p^3 \log ^5(x)+\frac {3}{4} b m n p^2 \log ^4(x) \log \left (f x^p\right )-\frac {1}{2} b m n p \log ^3(x) \log ^2\left (f x^p\right )+\frac {a \log ^4\left (f x^p\right )}{4 p}-\frac {3}{4} b n p^3 \log ^4(x) \log \left (1+\frac {d x^{-m}}{e}\right )+2 b n p^2 \log ^3(x) \log \left (f x^p\right ) \log \left (1+\frac {d x^{-m}}{e}\right )-\frac {3}{2} b n p \log ^2(x) \log ^2\left (f x^p\right ) \log \left (1+\frac {d x^{-m}}{e}\right )+b n p^3 \log ^4(x) \log \left (d+e x^m\right )-\frac {b n p^3 \log ^3(x) \log \left (-\frac {e x^m}{d}\right ) \log \left (d+e x^m\right )}{m}-3 b n p^2 \log ^3(x) \log \left (f x^p\right ) \log \left (d+e x^m\right )+\frac {3 b n p^2 \log ^2(x) \log \left (-\frac {e x^m}{d}\right ) \log \left (f x^p\right ) \log \left (d+e x^m\right )}{m}+3 b n p \log ^2(x) \log ^2\left (f x^p\right ) \log \left (d+e x^m\right )-\frac {3 b n p \log (x) \log \left (-\frac {e x^m}{d}\right ) \log ^2\left (f x^p\right ) \log \left (d+e x^m\right )}{m}-b n \log (x) \log ^3\left (f x^p\right ) \log \left (d+e x^m\right )+\frac {b n \log \left (-\frac {e x^m}{d}\right ) \log ^3\left (f x^p\right ) \log \left (d+e x^m\right )}{m}-\frac {1}{4} b p^3 \log ^4(x) \log \left (c \left (d+e x^m\right )^n\right )+b p^2 \log ^3(x) \log \left (f x^p\right ) \log \left (c \left (d+e x^m\right )^n\right )-\frac {3}{2} b p \log ^2(x) \log ^2\left (f x^p\right ) \log \left (c \left (d+e x^m\right )^n\right )+b \log (x) \log ^3\left (f x^p\right ) \log \left (c \left (d+e x^m\right )^n\right )+\frac {b n p \log (x) \left (p^2 \log ^2(x)-3 p \log (x) \log \left (f x^p\right )+3 \log ^2\left (f x^p\right )\right ) \text {Li}_2\left (-\frac {d x^{-m}}{e}\right )}{m}-\frac {b n \left (p \log (x)-\log \left (f x^p\right )\right )^3 \text {Li}_2\left (1+\frac {e x^m}{d}\right )}{m}+\frac {3 b n p \log ^2\left (f x^p\right ) \text {Li}_3\left (-\frac {d x^{-m}}{e}\right )}{m^2}+\frac {6 b n p^2 \log \left (f x^p\right ) \text {Li}_4\left (-\frac {d x^{-m}}{e}\right )}{m^3}+\frac {6 b n p^3 \text {Li}_5\left (-\frac {d x^{-m}}{e}\right )}{m^4} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(Log[f*x^p]^3*(a + b*Log[c*(d + e*x^m)^n]))/x,x]

[Out]

(-3*b*m*n*p^3*Log[x]^5)/10 + (3*b*m*n*p^2*Log[x]^4*Log[f*x^p])/4 - (b*m*n*p*Log[x]^3*Log[f*x^p]^2)/2 + (a*Log[
f*x^p]^4)/(4*p) - (3*b*n*p^3*Log[x]^4*Log[1 + d/(e*x^m)])/4 + 2*b*n*p^2*Log[x]^3*Log[f*x^p]*Log[1 + d/(e*x^m)]
- (3*b*n*p*Log[x]^2*Log[f*x^p]^2*Log[1 + d/(e*x^m)])/2 + b*n*p^3*Log[x]^4*Log[d + e*x^m] - (b*n*p^3*Log[x]^3*
Log[-((e*x^m)/d)]*Log[d + e*x^m])/m - 3*b*n*p^2*Log[x]^3*Log[f*x^p]*Log[d + e*x^m] + (3*b*n*p^2*Log[x]^2*Log[-
((e*x^m)/d)]*Log[f*x^p]*Log[d + e*x^m])/m + 3*b*n*p*Log[x]^2*Log[f*x^p]^2*Log[d + e*x^m] - (3*b*n*p*Log[x]*Log
[-((e*x^m)/d)]*Log[f*x^p]^2*Log[d + e*x^m])/m - b*n*Log[x]*Log[f*x^p]^3*Log[d + e*x^m] + (b*n*Log[-((e*x^m)/d)
]*Log[f*x^p]^3*Log[d + e*x^m])/m - (b*p^3*Log[x]^4*Log[c*(d + e*x^m)^n])/4 + b*p^2*Log[x]^3*Log[f*x^p]*Log[c*(
d + e*x^m)^n] - (3*b*p*Log[x]^2*Log[f*x^p]^2*Log[c*(d + e*x^m)^n])/2 + b*Log[x]*Log[f*x^p]^3*Log[c*(d + e*x^m)
^n] + (b*n*p*Log[x]*(p^2*Log[x]^2 - 3*p*Log[x]*Log[f*x^p] + 3*Log[f*x^p]^2)*PolyLog[2, -(d/(e*x^m))])/m - (b*n
*(p*Log[x] - Log[f*x^p])^3*PolyLog[2, 1 + (e*x^m)/d])/m + (3*b*n*p*Log[f*x^p]^2*PolyLog[3, -(d/(e*x^m))])/m^2
+ (6*b*n*p^2*Log[f*x^p]*PolyLog[4, -(d/(e*x^m))])/m^3 + (6*b*n*p^3*PolyLog[5, -(d/(e*x^m))])/m^4

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Maple [F]
time = 0.08, size = 0, normalized size = 0.00 \[\int \frac {\ln \left (f \,x^{p}\right )^{3} \left (a +b \ln \left (c \left (d +e \,x^{m}\right )^{n}\right )\right )}{x}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(ln(f*x^p)^3*(a+b*ln(c*(d+e*x^m)^n))/x,x)

[Out]

int(ln(f*x^p)^3*(a+b*ln(c*(d+e*x^m)^n))/x,x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(f*x^p)^3*(a+b*log(c*(d+e*x^m)^n))/x,x, algorithm="maxima")

[Out]

-1/4*(b*p^3*log(x)^4 - 4*b*p^2*log(f)*log(x)^3 + 6*b*p*log(f)^2*log(x)^2 - 4*b*log(f)^3*log(x) - 4*b*log(x)*lo
g(x^p)^3 + 6*(b*p*log(x)^2 - 2*b*log(f)*log(x))*log(x^p)^2 - 4*(b*p^2*log(x)^3 - 3*b*p*log(f)*log(x)^2 + 3*b*l
og(f)^2*log(x))*log(x^p))*log((d + e^(m*log(x) + 1))^n) - integrate(-1/4*(4*b*d*log(c)*log(f)^3 + 4*a*d*log(f)
^3 + 4*(b*d*log(c) + a*d - (b*m*n*e*log(x) - (b*log(c) + a)*e)*x^m)*log(x^p)^3 + 6*(2*b*d*log(c)*log(f) + 2*a*
d*log(f) + (b*m*n*p*e*log(x)^2 - 2*b*m*n*e*log(f)*log(x) + 2*(b*log(c)*log(f) + a*log(f))*e)*x^m)*log(x^p)^2 +
(b*m*n*p^3*e*log(x)^4 - 4*b*m*n*p^2*e*log(f)*log(x)^3 + 6*b*m*n*p*e*log(f)^2*log(x)^2 - 4*b*m*n*e*log(f)^3*lo
g(x) + 4*(b*log(c)*log(f)^3 + a*log(f)^3)*e)*x^m + 4*(3*b*d*log(c)*log(f)^2 + 3*a*d*log(f)^2 - (b*m*n*p^2*e*lo
g(x)^3 - 3*b*m*n*p*e*log(f)*log(x)^2 + 3*b*m*n*e*log(f)^2*log(x) - 3*(b*log(c)*log(f)^2 + a*log(f)^2)*e)*x^m)*
log(x^p))/(d*x + x*e^(m*log(x) + 1)), x)

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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 423 vs. \(2 (162) = 324\).
time = 0.36, size = 423, normalized size = 2.63 \begin {gather*} \frac {24 \, b n p^{3} {\rm polylog}\left (5, -\frac {x^{m} e}{d}\right ) + 4 \, {\left (b m^{4} \log \left (c\right ) + a m^{4}\right )} \log \left (f\right )^{3} \log \left (x\right ) + 6 \, {\left (b m^{4} p \log \left (c\right ) + a m^{4} p\right )} \log \left (f\right )^{2} \log \left (x\right )^{2} + 4 \, {\left (b m^{4} p^{2} \log \left (c\right ) + a m^{4} p^{2}\right )} \log \left (f\right ) \log \left (x\right )^{3} + {\left (b m^{4} p^{3} \log \left (c\right ) + a m^{4} p^{3}\right )} \log \left (x\right )^{4} - 4 \, {\left (b m^{3} n p^{3} \log \left (x\right )^{3} + 3 \, b m^{3} n p^{2} \log \left (f\right ) \log \left (x\right )^{2} + 3 \, b m^{3} n p \log \left (f\right )^{2} \log \left (x\right ) + b m^{3} n \log \left (f\right )^{3}\right )} {\rm Li}_2\left (-\frac {x^{m} e + d}{d} + 1\right ) + {\left (b m^{4} n p^{3} \log \left (x\right )^{4} + 4 \, b m^{4} n p^{2} \log \left (f\right ) \log \left (x\right )^{3} + 6 \, b m^{4} n p \log \left (f\right )^{2} \log \left (x\right )^{2} + 4 \, b m^{4} n \log \left (f\right )^{3} \log \left (x\right )\right )} \log \left (x^{m} e + d\right ) - {\left (b m^{4} n p^{3} \log \left (x\right )^{4} + 4 \, b m^{4} n p^{2} \log \left (f\right ) \log \left (x\right )^{3} + 6 \, b m^{4} n p \log \left (f\right )^{2} \log \left (x\right )^{2} + 4 \, b m^{4} n \log \left (f\right )^{3} \log \left (x\right )\right )} \log \left (\frac {x^{m} e + d}{d}\right ) - 24 \, {\left (b m n p^{3} \log \left (x\right ) + b m n p^{2} \log \left (f\right )\right )} {\rm polylog}\left (4, -\frac {x^{m} e}{d}\right ) + 12 \, {\left (b m^{2} n p^{3} \log \left (x\right )^{2} + 2 \, b m^{2} n p^{2} \log \left (f\right ) \log \left (x\right ) + b m^{2} n p \log \left (f\right )^{2}\right )} {\rm polylog}\left (3, -\frac {x^{m} e}{d}\right )}{4 \, m^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(f*x^p)^3*(a+b*log(c*(d+e*x^m)^n))/x,x, algorithm="fricas")

[Out]

1/4*(24*b*n*p^3*polylog(5, -x^m*e/d) + 4*(b*m^4*log(c) + a*m^4)*log(f)^3*log(x) + 6*(b*m^4*p*log(c) + a*m^4*p)
*log(f)^2*log(x)^2 + 4*(b*m^4*p^2*log(c) + a*m^4*p^2)*log(f)*log(x)^3 + (b*m^4*p^3*log(c) + a*m^4*p^3)*log(x)^
4 - 4*(b*m^3*n*p^3*log(x)^3 + 3*b*m^3*n*p^2*log(f)*log(x)^2 + 3*b*m^3*n*p*log(f)^2*log(x) + b*m^3*n*log(f)^3)*
dilog(-(x^m*e + d)/d + 1) + (b*m^4*n*p^3*log(x)^4 + 4*b*m^4*n*p^2*log(f)*log(x)^3 + 6*b*m^4*n*p*log(f)^2*log(x
)^2 + 4*b*m^4*n*log(f)^3*log(x))*log(x^m*e + d) - (b*m^4*n*p^3*log(x)^4 + 4*b*m^4*n*p^2*log(f)*log(x)^3 + 6*b*
m^4*n*p*log(f)^2*log(x)^2 + 4*b*m^4*n*log(f)^3*log(x))*log((x^m*e + d)/d) - 24*(b*m*n*p^3*log(x) + b*m*n*p^2*l
og(f))*polylog(4, -x^m*e/d) + 12*(b*m^2*n*p^3*log(x)^2 + 2*b*m^2*n*p^2*log(f)*log(x) + b*m^2*n*p*log(f)^2)*pol
ylog(3, -x^m*e/d))/m^4

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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(ln(f*x**p)**3*(a+b*ln(c*(d+e*x**m)**n))/x,x)

[Out]

Timed out

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(f*x^p)^3*(a+b*log(c*(d+e*x^m)^n))/x,x, algorithm="giac")

[Out]

integrate((b*log((x^m*e + d)^n*c) + a)*log(f*x^p)^3/x, x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\ln \left (f\,x^p\right )}^3\,\left (a+b\,\ln \left (c\,{\left (d+e\,x^m\right )}^n\right )\right )}{x} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((log(f*x^p)^3*(a + b*log(c*(d + e*x^m)^n)))/x,x)

[Out]

int((log(f*x^p)^3*(a + b*log(c*(d + e*x^m)^n)))/x, x)

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